The concept of density.
Figure below Shows two identical flasks one filled with water to 250cm3 mark and the other filled with kerosene to the same 250cm3 mark, when measured in electronic balance the flask filled with water is found to be heavier than that filled with kerosene why? The answer is in finding the mass per unit volume of kerosene and water in respective flasks.
Mass per unit volume of water is 250g/ 250cm3 this is 1g/cm3.
Mass per unit volume of kerosene is 200g/ 250cm3this is 0.8g/cm3.
The results 1g/cm3 and 0.8g/cm3 are the densities of water and kerosene respectively.
Therefore the density of a substance is the mass per unit volume of a given substance.
The SI unit of density is kilogram per meter cubic (kg/m3) also gram per centimeter cubic (g/cm3). The symbol for density is rho (ρ) ρ=mass/volume.
Example 1.
A block of ice with volume 5.5m3 has a mass of 5060kg find the density of ice.
Solution
Volume of block=5.5m3
Mass of block=5060kg
Density=mass /volume
=5060/5.5m3.
=920kg/m3.
The density of ice is 920kg/m3.
Example 2.
A silver cylindrical rod has a length of 0.5m and radius of 0.4m,find the density of the rod if its mass is 2640kg.
Solution
Mass of cylinder=2640kg
Volume of cylinder= πr²h
=3.14 x 0.4 2 x 0.5
=0.2512m3
Density=mass/volume
=10509kg/m3.
Example3.
A stone has a mass of 112.5g.when the stone totally immersed in water contained in measuring cylinder displaced water from 50cm3 to 95cm3.find the density of the stone.
Solution
Mass of the stone=112.5g
Volume of stone=95cm3-50cm3=45cm3
Density=mass/volume
=2.5g/cm3.
Example
4.
Beaker
contain 262.5cm3 of a certain liquid weigh 410g,if the mass of an empty dry beaker
is 200g,find the density of the liquid.
Solution
Mass
of liquid=410g-200g=210g
Volume
of liquid=262.5cm3.
Density=mass/volume
=0.8g/cm3.
DENSITY
BOTTLE
The density bottle
(pycnometer) consists of ground glass stopper with a fine hole through it.
The function of the
fine hole in a stopper is that, when the bottle is filled and the stopper is inserted,
the excess liquid rises through the hole and runs down outside the bottle, by
this way the bottle will always contain the same volume of whatever the liquid
is filled in provided the temperature remains constant.
density bottle
the
bottle is used to measure density and relative density, relative density is
comparison of one density to another, thus a density of a given volume of a
substance to a density of equal volume of referenced substance, for example a
ratio of a density of a given volume of
substance to a density of an equal volume of water, this is referred to a relative
density of a given substance or Specific gravity of a given substance. The term
specific gravity is used when the reference substance is water.
Measurement of density of liquid by
relative density bottle
ü The mass of bottle is found when dry and
empty
ü The bottle is then filled with the liquid
density is to be determined
ü The stopper is then inserted causing the
liquid to overflow
ü The bottle is dried up by using blotting
paper
ü The mass of the liquid and the bottle is
found
ü Density is found from the collected data
Mass
of empty bottle=m1g
Volume of liquid
in the bottle=V
mass of bottle
and the liquid=m2g
mass of liquid
only=(m2-m1)g
density= mass /volume
density=
. (m2-m1)g/V
The
volume of the bottle is known, usually 25ml, 30ml or 50ml
Example 1
A
30ml density bottle was filled with kerosene and found to weigh 86g.if the mass
empty dry bottle was 62g, find the density of kerosene.
Solution
Mass of empty
bottle=62g
Mass of bottle and
kerosene=86g
Mass of kerosene
only=86g-62g=24g
Density= mass /volume
=24g/30ml
=0.8g/cm3.
Determination of
densities of granules and sand
To
find the density of sand or granules such as lead shots a density bottle is
used as follows
1. Find the mass of empty dry density bottle
mo
2. Put some granules and find the mass m1
=( mass of empty bottle + mass of granules)
3. Pour water in the bottle until it is full
and find mass m2 = (
mass of bottle + mass of granules + mass of water on top of granules)
4. Find the mass of bottle filled with water
only m3 =( mass of
bottle + mass of water)
The mass of sand = (m1-m0) g
Mass of water above the
sand = (m2-m1) g
Mass of water filling
the bottle = (m3-m0)
g
Since
density of water is 1g/cm³
Volume
of sand = [(m1+m3)-(mo+m2)]/1g/cm³
= [(m1+m3)-(mo+m2)]
cm³
Density=mass/volume
Example 1
Given
the data below find the density of granules
Mass
of empty dry density bottle =18g
Mass
of density bottle and granules=131g
Mass
of density bottle and granules together with water on top =171g
Mass
of density bottle full of water=68g
RELATIVE DENSITY
Relative density of a substance is the
ratio of the density of substance to the density of water.
Or
Relative density of a substance is the ratio
of mass of any volume of substance to the mass of an equal volume of water.
Example
1
To
measure relative density of liquid by density bottle
ü
Find
mass of empty bottle –m0
ü
Find
mass of bottle and liquid-m1
ü
Empty
the bottle and rinse it with water
ü
Fill
the bottle with water and find mass m2
Mass of liquid= (m1-m0)g
Mass of equal volume of water= (m2-m0)g
Since
comparison of density is done with water (referenced substance) the other name
of the ratio is specific gravity of a
given substance. Because the density of water is 1g/cm³.Relative density has no
units it is simply a number or ratio.
Example
The
mass of density bottle is 19g when dry and empty, 45g when filled with water
and 40g when full of liquid x. calculate the density of the liquid x.
Determinations
of relative density by eureka can method
ü Find the mass m₀ g of solid
ü Fill the eureka can and let water overflow until last drop
ü Place under the spout of overflow can a
clean dry beaker of mass m₁ g.
ü Lower the solid slowly with thin thread
until it is totally immersed
ü Obtain the mass of water that overflow
from the eureka can and the beaker itself m₂ g.
The
volume of water overflows into a beaker is equal to the volume of solid
Mass of solid = m₀ g
Mass of beaker and water=m₂ g
Mass of beaker=m ₁g.
Mass of water only = (m₂-m₁)g
EXAMPLE
A
certain piece of metal has a mass of 282.5 g,if when the block was totally
immersed in overflow can displaced water in a beaker of mass 20 g.if the mass of
water and the beaker was 45 g,find the relative density of the metal.
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ReplyDeleteA density bottle weighs 3.4N when empty, 5N when filled with water and 6.4N when filled with a substance 'A'. Calculate the density of the substance 'A'.
Take weight in air devide by upthrust in water.
DeleteR.d = ml -mo
Delete__ -------
MW - mo
6.5- 3.4
---------
5.0- 3.4
=3.1
---
1.6
=2.1
Great job...
ReplyDeleteGud work
ReplyDeleteDensity Bottle = 3.4N .....(1)
ReplyDeleteDensity Bottle + Water = 5N ..(2)
Mass of Water = 5N-3.4N
= 1.6N
Mass of Substance A
= 6.4N- Empty Bottle
= 6.4N- 3.4
= 3.0N
Relative Density =
Mass of substance / Mass of water
= 3.0N/1.6N
= 1.875N
Density of Substance = 1.875N
Weight of empty bottle = 3.4N
DeleteWeight of bottle+Water = 5N
Weight of bottle+liquid A = 6.4N
R.D= Wa-Wb /Ww-Wb
= 6.4-3.4/5-3.4
= 1.875N
Density of liquid A
= R.D * Density of water
= 1.875*1000
=1875kg/m3
The concept of density and RD is absolutely clear. Reqst many more such papers covering other topics also sir...🙂
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ReplyDeleteA solid displaced 8.5cm3 of liquid when floating in a certain liquid and 11.5cm3 when fully submerged in the same liquid.The density of the solid is 0.8g/cm3.Determine (1)the upthrust on the solid when floating (2)The density of the liquid (3)The upthrust on the solid when fully submerged
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ReplyDeleteThe mass of the volume of a substance is 50g. The mass of the volume immersed in the water is 35g.
Find the relative density of the substance
Find the density of the substance
These were the only two parameters they gave in the question
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Ans is 50/(50-35)=3.3
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ReplyDeleteA piece of iron weighs 250N in air and 200N in a liquid of density 1000kg/m3. Calculate the volume of iron
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ReplyDeleteCan someone one help me this question: A piece of metal weighs 0.54N in air and 0.24N when immersed in water. Find
ReplyDeleteI. It's relative density
II. It's apparent weight in a liquid of density 1.2g/cm³
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ReplyDelete100g of water mixed with 60g liquid of density 1.2g/cm³.assume no change in volume. What is the average relative density of the mixture?
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ReplyDeleteA bottle full of water has a mass of 45g, when full of Mercury its mass is 360g if the mass of empty bottle is 20g when empty calculate density of mercury
ReplyDeleteMass of bottle + water = 45g
DeleteMass of bottle + mercury = 360g
Mass of emty-dry bottle = 20g
Mass of water only = 45g - 20g
= 25g
Mass of mercury only = 360g-20g
= 340g
Relative Density = Density of substance/density of water.
Where Density of water = 1.0g/cm^3
R.D = 340g/25 = 13.6
But R.D = density of substance/density of water
Therefore 13.6 = density of substance/density of water.
Density of substance = 13.6X1.0g/cm^3
= 13.6g/cm^3
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ReplyDeleteExplain relative density in terms of mass
ReplyDeleteExplain relative density in terms of mass
ReplyDeleteRelative density is the ratio mass of the given substance yo the mass of equal volume of water
DeleteA relative density of a substance is 2.8.What is it's density?
ReplyDeleteIts density is equal to 2.8g/cm^3
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ReplyDeleteA fluid having a relative density of 0.8 is mixed with 10 kg of water. Determine the mass of the mixing fluid if the mixture has relative density 0f 0.9.
a. 12kg
b. 8kg
c. 4kg
d. 16kg
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ReplyDeleteFind density of sand from the following information
ReplyDelete( Mass of density bottle filled with water 70.64g
( Mass of bottle filled with water + Sand (outside the bottle) = 78.79g
( Mass of bottle + water + sand (inside the bottle) = 75.66g
…
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ReplyDeletedetermine the minimum volume of copper that must be attached to Cork of mass 25g so that the will just submerged in water. given that relatative density of copper is 9 and that of cork is 0.25
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ReplyDelete360g of liquid A of density, 1.20g/cm³ were missed with 100g of liquid B of Density 1.00g/cm³ Showing your working, calculate
ReplyDeletea) the volume of the mixture
b)the Density of the mixture
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Delete360g of liquid A of density, 1.20g/cm³ were missed with 100g of liquid B of Density 1.00g/cm³ Showing your working, calculate
ReplyDeletea) the volume of the mixture
b)the Density of the mixture
A piece of metal weghs 0.6 N in air and 0.5 N when fully submerged in water.When the metal is fully submerged in liquid L it weighs 0.54 N. Determine the relative relative density of the metal
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